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Biochemistry-I MCQs | BIO202 MCQs | Set 7

 Biochemistry-I MCQs | BIO202 MCQs | Set 7

MCQs (Multiple Choice Questions)

1)    Choose a suger out of the following that is non reactive to Seliwanoff reagent?

    a)        Sucrose

    b)        Fructose

    c)        Inulin

    d)       Ribose

Correct Answer: 

The correct answer is  'd'.

Explanation:

Seliwanoff's reagent is used to distinguish between ketose and aldose sugars. Ketose sugars react with Seliwanoff's reagent to produce a cherry-red color, while aldose sugars do not react.

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2)    Choose a keto triose:  

    a)        Glyceraldehyde

    b)        Dihydroxyacetone

    c)        Erythrose

    d)       Arabinose

Correct Answer: 

The correct answer is  'b'.

Explanation:

Dihydroxyacetone is a keto triose. Trioses are three-carbon sugars, and dihydroxyacetone has a ketone functional group (C=O) in its structure, making it a keto sugar.

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3)    A pentose sugar present in the heart muscle is:

    a)       Xylose 

    b)       Xylulose

    c)       Lyxose

    d)       Aldose

Correct Answer: 

The correct answer is  'c'.

Explanation:

Lyxose is a pentose sugar that can be found in various tissues, including the heart muscle. It is an aldose, which means it is a sugar with an aldehyde functional group.

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4)    d-Glucose and I-Glucose are:

    a)        Stereo isomers

    b)        Anomers

    c)        Keto-Aldose

    d)       Optical isomers

Correct Answer: 

The correct answer is  'd'.

Explanation:

d-Glucose and l-Glucose are optical isomers, also known as enantiomers. They have the same chemical formula but differ in their three-dimensional spatial arrangement, making them non-superimposable mirror images of each other. Stereoisomers are a broader category that includes enantiomers, diastereomers, and others. Anomers refer to specific types of stereoisomers related to the cyclic structure of sugars.

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5)    All the following tests are positive for Lactose except ________.

    a)        Benedict

    b)        Barfoed

    c)         Molisch

    d)        Osazone

Correct Answer: 

The correct answer is  'd'.

Explanation:

The osazone test is used to identify monosaccharides, such as glucose and fructose. Lactose is a disaccharide made up of glucose and galactose. Therefore, lactose will not give a positive osazone test.

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6)     Glucose can have _____ isomers due to the presence of 4 asymmetric carbon atoms.

    a)      4

    b)      2

    c)       12

    d)       16

Correct Answer: 

The correct answer is  'd'.

Explanation:

Glucose can have 16 stereoisomers due to the presence of 4 asymmetric (chiral) carbon atoms. Each chiral carbon can have two possible configurations (R and S), and when you multiply the possibilities for all four chiral carbons, you get a total of `2^4` = 16 stereoisomers.

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7)    Fructose and Ribulose are:

    a)        Epimers

    b)       Anomers

    c)        Ketoses

    d)       Ketose-Aldose isomers

Correct Answer: 

The correct answer is  'c'.

Explanation:

Ketoses are monosaccharides that have a ketone functional group. Fructose and ribulose are both ketoses.

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8)    The compounds having same structural formula but differing in configuration around one carbon atom are called:

    a)        Optical isomers

    b)        Anomers

    c)        Stereo isomers

    d)       Epimers

Correct Answer: 

The correct answer is  'd'.

Explanation:

The compounds having the same structural formula but differing in configuration around one carbon atom are called epimers. Epimers are a type of stereoisomer and are characterized by their differences at a single chiral center. Anomers are a specific type of epimer related to the cyclic structure of sugars. Stereoisomers is a broader term that encompasses various types of isomers that differ in their spatial arrangement. Optical isomers (enantiomers) are a subtype of stereoisomers. 

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9)     What does the following equation represent?

`alpha`-D Glucose + 112o`\rightarrow`+52.5o`\rightarrow`+19o`\beta` - D glucose

    a)        Stereois omerism

    b)        Optical isomerism

    c)         Mutarotion

    d)        Epimerization

Correct Answer: 

The correct answer is  'c'.

Explanation:

The equation represents mutarotation, which is a phenomenon in which the specific rotation (observed optical rotation) of an optically active compound changes over time when dissolved in a solvent. In this case, it's referring to the mutarotation of α-D-glucose to β-D-glucose, where the specific rotation values change as the glucose solution shifts between the α and β forms. Mutarotation is a characteristic of compounds that can exist in different anomeric forms (such as α and β) and is a type of optical isomerism.

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10)   The carbohydrate of honey is  

    a)        Fucose

    b)        Maltose

    c)        Lactose

    d)       Fructose

Correct Answer: 

The correct answer is  'd'.

Explanation:

Fructose is a monosaccharide, which means that it is the simplest form of carbohydrate. It is a ketose sugar, which means that it has a ketone functional group. Fructose is one of the sweetest sugars, and it is responsible for the sweetness of honey.

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