Compute a simple average of relatives' price indices using A. M and Median
Simple Average of Relatives' Price Indices
Question
Given the prices of three commodities, Using 1990 as the base period, compute, a simple average of relatives' price indices using
- A.M
- Median
Year |
Prices |
||
A |
B |
C |
|
1990 |
30.00 |
12.00 |
20.00 |
1991 |
35.50 |
13.50 |
23.50 |
1992 |
32.50 |
14.50 |
25.00 |
1993 |
32.50 |
14.00 |
25.00 |
Solutions:
Price Relatives
Year |
Price Relatives |
||
A |
B |
C |
|
1990 |
(30.00/30.00)*100= 100 |
(12.00/12.00)*100 |
(20.00/20.00)*100=100 |
1991 |
(35.50/30.00)*100=101.6 |
(13.50/12.00)*100 = 112.5 |
(23.50/20.00)*100=117.5 |
1992 |
(32.50/30.00)*100=108.3 |
(14.50/12.00)*100 = 120.8 |
(25.00/20.00)*100=125 |
1993 |
(32.50/30.00)*100=108.3 |
(14.00/12.00)*100=116.6 |
(25.00/20.00)*100=125 |
Now A.M and Median
A.M = `\frac{Sum of all observations}{Total number of Observations}`
Year |
Price Relatives |
Total |
A.M |
Median |
||
A |
B |
C |
||||
1990 |
100 |
100 |
100 |
300 |
300/3=100 |
100 |
1991 |
101.6 |
112.5 |
117.5 |
331.6 |
331/3=110.53 |
112.5 |
1992 |
108.3 |
120.8 |
125 |
354.1 |
354.1/3=118.03 |
120.8 |
1993 |
108.3 |
116.6 |
125 |
349.9 |
349.9/3=116.63 |
116.6 |
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